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With \( \beta = 100 \) that stage's collector current is

  • A.0.24 mA, dividing rather than multiplying by the current gain
  • B.3.6 mA, which would require a current gain of about 150
  • C.2.4 mA
  • D.24 mA

Answer: C

Multiplying the base current by the gain:

\[ I_{C} = 100 \times 24 \ \mathrm{\mu A} = 2.4 \ \mathrm{mA} \]

so 2.4 mA. If beta were 300 the current would be 7.2 mA and the stage would very likely saturate. Working out both extremes of the beta range rather than the nominal value is what reveals whether a bias arrangement will survive a device change.

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