Discussion
A divider bias stage has \( R_{1} = 47 \ \mathrm{k\Omega} \), \( R_{2} = 10 \ \mathrm{k\Omega} \) and \( V_{CC} = 12 \ \mathrm{V} \). The base voltage is about
Answer: D
Applying the divider ratio:
\[ V_{B} = 12 \times \frac{10}{57} \approx 2.1 \ \mathrm{V} \]
giving about 2.1 volts, before allowing for the base current the divider also has to supply. The unloaded ratio is the starting point and the loading correction is small in a stiff divider, which is exactly the approximation stiffness buys.
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