Discussion
A stage carries \( 2 \ \mathrm{mA} \) with \( R_{E} = 1 \ \mathrm{k\Omega} \). If beta doubles, the emitter current changes by about
Answer: B
The emitter current is set by the base voltage and the emitter resistor, neither of which depends on beta:
\[ I_{E} = \frac{V_{B} - 0.7}{R_{E}} \]
so the change is under one per cent, arising only from the slightly reduced base current loading the divider. That near-immunity to beta is what the arrangement was chosen for, and it is why the same circuit works with any device in the family.
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