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Why is measuring the emitter voltage often more informative than the base voltage?

  • A.It shows whether the divider is stiff enough for the device fitted
  • B.It reveals the device's current gain without any further calculation
  • C.It gives the emitter current directly
  • D.It is less affected by the loading of a test meter on the circuit

Answer: C

The emitter voltage divided by the emitter resistor gives the current at once, and the current is what the design actually specifies. Meter loading is a genuine but secondary consideration, stiffness needs two measurements to assess, and beta needs the base current as well. Measuring at the point where a single reading converts straight into the quantity of interest is worth a moment's thought before probing anything. Most errors on this topic come from carrying a result across from a neighbouring scheme where it does not hold.

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