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A class A stage draws \( 20 \ \mathrm{mA} \) from \( 12 \ \mathrm{V} \). Its quiescent dissipation is

  • A.480 mW
  • B.240 mW
  • C.120 mW, taking half the supply as the working voltage
  • D.60 mW, which would be the figure at a quarter of the current

Answer: B

Multiplying supply by current:

\[ P = 12 \times 20\mathrm{m} = 240 \ \mathrm{mW} \]

giving 240 milliwatts, of which some is in the resistors and the rest in the device. At best a quarter of it reaches the load, so the useful output is around sixty milliwatts. Computing the power drawn before the power delivered puts the efficiency question in the right order.

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