Discussion
A stage has \( R_{E} = 1 \ \mathrm{k\Omega} \) carrying \( 2 \ \mathrm{mA} \) on a \( 12 \ \mathrm{V} \) supply. The fraction of the supply spent on the emitter is
Answer: B
The drop and the ratio follow directly:
\[ \begin{aligned} V_{E} &= 2\mathrm{m} \times 1000 = 2 \ \mathrm{V} \\ \frac{V_{E}}{V_{CC}} &= \frac{2}{12} \approx 17\% \end{aligned} \]
so about 17 per cent, a little above the usual tenth but perfectly reasonable where stability matters more than swing. Expressing a design choice as a fraction of the supply makes it comparable across circuits running on different rails. Framing the question as which quantity the change acts upon makes the answer follow without calculation.
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