Discussion
Halving that emitter resistor while holding the current constant requires the base voltage to change to
Answer: C
The emitter voltage halves and the junction drop is unchanged:
\[ \begin{aligned} V_{E} &= 1 \ \mathrm{V} \\ V_{B} &= 1 + 0.7 = 1.7 \ \mathrm{V} \end{aligned} \]
giving 1.7 volts, so the divider must be reproportioned. The current is unchanged but the stabilisation is halved, which is the cost of the extra volt of headroom gained. Every such adjustment moves one quantity and one specification together.
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