Discussion
With that Thevenin resistance and a base voltage of \( 2 \ \mathrm{V} \) from a \( 12 \ \mathrm{V} \) supply, the two divider resistors are about
Answer: A
The ratio fixes their proportion and the parallel value fixes their size:
\[ \begin{aligned} \frac{R_{2}}{R_{1}+R_{2}} &= \frac{2}{12} \\ R_{1} \| R_{2} &= 15 \ \mathrm{k\Omega} \end{aligned} \]
which gives about 90 k and 18 k, the larger arm to the supply. Reversing them would put the base at ten volts. Two conditions determine two unknowns, and setting both up before solving avoids the guesswork.
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