Discussion
A man can row with a speed of 15 kmph in still water. If the stream flows at 5 kmph, then the speed in downstream is?
Answer: C
With \( b \) the still-water speed and \( r \) the stream's,
\[ \text{downstream} = b + r, \qquad \text{upstream} = b - r \]
\[ b + r = 15 + 5 = 20 \text{ kmph} \]
Downstream the current helps, so the speeds add. Upstream they would subtract, giving 10 kmph - which is why 10 is offered as a distractor.
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