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If a boat goes 7 km upstream in 42 minutes and the speed of the stream is 3 kmph, then the speed of the boat in still water is

  • A.12 kmph
  • B.13 kmph
  • C.14 kmph
  • D.15 kmph

Answer: B

With \( b \) the still-water speed and \( r \) the stream's,

\[ \text{downstream} = b + r, \qquad \text{upstream} = b - r \]

\[ 42 \text{ min} = \frac{42}{60} = 0.7 \text{ h} \]

\[ b - r = \frac{7}{0.7} = 10 \text{ kmph} \]

\[ b = (b - r) + r = 10 + 3 = 13 \text{ kmph} \]

The current is added back once, not twice: subtracting it gave the upstream speed, so restoring it gives the still-water speed. Adding it a second time would give the downstream speed of 16 kmph.

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