Discussion
The term (1/jw) on the logmagnitude plot has a slope of
Answer: A
The term \(1/j\omega\) has a slope of \(-20\) dB/decade, the first option. Its magnitude is \(1/\omega\), so the log magnitude is \(-20 \log \omega\) decibels, which falls by 20 dB for each tenfold rise in frequency.
The slope of +20 dB/decade belongs to a zero at the origin, \(j\omega\), and the slopes of \(\pm 40\) dB/decade belong to double poles or zeros at the origin, \(1/(j\omega)^2\) or \((j\omega)^2\). So the other options are wrong.
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