Discussion
A turbulent boundary layer at \( x = 2 \) m where \( Re_x = 4 \times 10^6 \) has a thickness nearest to
Answer: A
Using \( \delta = 0.37x/Re_x^{0.2} \), the denominator is \( (4 \times 10^6)^{0.2} = 21.0 \), so \( \delta = 0.37 \times 2/21.0 = 0.035 \) m. That is roughly seven times the laminar value at a comparable station, which is why turbulent layers matter so much for ducts and intakes.
No comment is present. Be the first to comment.
Loading…
Post your comment
Please log in or register to post a comment.
Examination Categories
- SSC Exams
- Banking Exams
- Teaching Exams
- Civil Services Exams
- Railways Exams
- Engineering Recruitment Exams
- Defence Exams
- State Government Exams
- Police Exams
- Insurance Exams
- Nursing Exams
- Other Government Exams
- NRA CET
- PG Entrance Exams
- Campus Placement
- MBA Entrance Exams
- CUET and UG Entrance
- Judiciary Exams
- Regulatory Body Exams
- Software Development