Discussion
A section of \( I = 10^6 \) mm\( ^4 \) and area \( 500 \) mm\( ^2 \) has a radius of gyration of nearest to
Answer: A
Correct answer: 44.7 mm
\[ r = \sqrt{\frac{I}{A}} = \sqrt{\frac{10^6}{500}} = \sqrt{2000} = 44.7\ \mathrm{mm}. \] The radius of gyration measures how far the material sits from the neutral axis, which is why a tube is so much better than a solid bar of the same area - the same material at a greater radius gives a larger \( r \).
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