Discussion
A column of \( 2 \) m effective length is braced at mid-span. Its critical load is multiplied by
Answer: C
A brace at mid-span halves the unsupported length, and the critical load varies inversely with the square of that length: \[ \frac{P_{2}}{P_{1}} = \left(\frac{L}{L/2}\right)^{2} = 2^{2} = 4 \] so the capacity is multiplied by four. A single well-placed brace is often the cheapest structural improvement available, since it adds almost no weight while quadrupling the buckling capacity.
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