Discussion
A parallelepiped of (2 m × 2 m) square cross-section and 10 m in length, is partially floating in water upto a depth of 1.2 m, with its longest side being horizontal. The specific gravity of the block is
Answer: B
The specific gravity is 0.6.
A floating body displaces its own weight of water. With the 10 m length horizontal, the block's cross-section is 2 m by 2 m and it sinks 1.2 m of its 2 m height, so the submerged fraction of its volume is 1.2/2:
\[ \begin{aligned} SG &= \frac{\rho_{\text{block}}}{\rho_{\text{water}}} = \frac{V_{\text{sub}}}{V} \\ &= \frac{1.2}{2} = 0.6 \end{aligned} \]
0.8 and 0.4 do not correspond to the given depth, and 0.5 would put the waterline at exactly mid-height, 1.0 m. The length of 10 m cancels and does not affect the answer.
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