Discussion
In one-way analysis of variance suppose there are k treatments and n is the total number of observations then the degree of freedom for error sum of squares will be ............
Answer: D
The error degrees of freedom are n - k.
In one-way ANOVA the total degrees of freedom, \(n - 1\), are split between treatments and error. Treatments take \(k - 1\), so error takes
\[ (n - 1) - (k - 1) = n - k \]
\(n - 1\) is the total, \(k - 1\) is for treatments, and \(nk - 1\) would apply only if \(n\) were the number of observations per treatment.
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