Discussion
Molasses at \( 50 \) per cent fermentable sugar gives ethanol at \( 90 \) per cent of the theoretical \( 0.511 \) kg per kg of sugar. From \( 1000 \) kg the ethanol is
Answer: C
Correct answer: 230 kg
Take the fermentable sugar, apply the theoretical yield, then the efficiency:
\[ \text{sugar} = 1000 \times 0.50 = 500\ \mathrm{kg} \]
\[ \text{theoretical} = 500 \times 0.511 = 255.5\ \mathrm{kg} \]
\[ \text{actual} = 255.5 \times 0.90 = 230\ \mathrm{kg} \]
The 0.511 figure is the stoichiometric maximum from the fermentation equation, the remainder of the sugar's mass leaving as carbon dioxide. No process reaches it, since some sugar goes to yeast growth and by-products.
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