Discussion
What is the output of this C code?
#include <stdio.h>
int main()
{
enum {ORANGE = 5, MANGO, BANANA = 4, PEACH};
printf("PEACH = %d\n", PEACH);
}
Answer: C
Correct answer: PEACH = 5
Enumerators continue from the previous value, and an explicit value restarts the sequence from that point.
So ORANGE = 5, MANGO becomes 6, BANANA = 4 resets the count, and PEACH follows at 5. ORANGE and PEACH therefore share the value 5, which C permits. The trap is expecting PEACH to continue from MANGO rather than from the explicitly reset BANANA.
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