Discussion
What is the output of following program?
#include <stdio.h>
#define macro(n, a, i, m) m##a##i##n
#define MAIN macro(n, a, i, m)
int MAIN()
{
printf("GeeksQuiz");
return 0;
}
Answer: B
Correct answer: GeeksQuiz
## is the token-pasting operator. macro(n, a, i, m) substitutes the arguments and joins them in the order m a i n, producing the single token main. So int MAIN() becomes int main(), the program is well formed, and it prints GeeksQuiz.
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