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What is the output of this program?

#include <stdio.h>
#define int char
main()
{
  int i=50;
  printf ("sizeof (i) =%d", sizeof (i));
}

 

  • A.2
  • B.4
  • C.8
  • D.1

Answer: D

Correct answer: 1

#define int char replaces the token int everywhere it appears afterwards, so int i = 50; becomes char i = 50; and sizeof(i) is 1. The preprocessor has no notion of keywords being reserved - it substitutes tokens, and int is just a token to it.

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