Discussion
What will be the output of the following C code?
#include <stdio.h>
void f()
{
#define sf 100
printf("%d",sf);
}
int main()
{
#define sf 99;
f();
printf("%d",sf);
}
Answer: A
Correct answer: error
The macro body is 99; - the semicolon is part of the text. Substituting it gives printf("%d",99;);, a syntax error. (The redefinition of sf without an intervening #undef is a second fault.) A #define for a constant should never end in a semicolon.
No comment is present. Be the first to comment.
Loading…
Post your comment
Please log in or register to post a comment.
Examination Categories
- SSC Exams
- Banking Exams
- Teaching Exams
- Civil Services Exams
- Railways Exams
- Engineering Recruitment Exams
- Defence Exams
- State Government Exams
- Police Exams
- Insurance Exams
- Nursing Exams
- Other Government Exams
- NRA CET
- PG Entrance Exams
- Campus Placement
- MBA Entrance Exams
- CUET and UG Entrance
- Judiciary Exams
- Regulatory Body Exams
- Software Development