Discussion

What will be the output of the program?

#include <stdio.h>
#define SQR(x)(x*x)

int main()
{
    int a, b=3;
    a = SQR(b+2);
    printf("%d\n", a);
    return 0;
}

Answer: B

Correct answer: 11

The macro body parenthesises the whole expression but not the parameter, so SQR(b+2) becomes (b+2*b+2):

\[ 3 + 6 + 2 = 11 \]

Only ((x)*(x)) would give the intended \(5^2 = 25\).

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