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What will be the output of the program?

#include <stdio.h>
#define FUN(i, j) i##j

int main()
{
    int va1=10;
    int va12=20;
    printf("%d\n", FUN(va1, 2));
    return 0;
}

 

  • A.10
  • B.20
  • C.1020
  • D.12

Answer: B

Correct answer: 20

## pastes its operands into a single token, so FUN(va1, 2) becomes va12 - the name of the second variable. The printf therefore prints 20.

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