Discussion
What will be the output of the program?
#include <stdio.h>
#define str(x) #x
#define Xstr(x) str(x)
#define oper multiply
int main()
{
char *opername = Xstr(oper);
printf("%s\n", opername);
return 0;
}
Answer: C
Correct answer: print 'multiply'
This is the standard two-level stringizing idiom. A macro argument is not expanded before # is applied, so str(oper) would give "oper". Going through Xstr first forces the argument to be expanded - oper becomes multiply - and only then is it stringized, giving "multiply".
No comment is present. Be the first to comment.
Loading…
Post your comment
Please log in or register to post a comment.
Examination Categories
- SSC Exams
- Banking Exams
- Teaching Exams
- Civil Services Exams
- Railways Exams
- Engineering Recruitment Exams
- Defence Exams
- State Government Exams
- Police Exams
- Insurance Exams
- Nursing Exams
- Other Government Exams
- NRA CET
- PG Entrance Exams
- Campus Placement
- MBA Entrance Exams
- CUET and UG Entrance
- Judiciary Exams
- Regulatory Body Exams
- Software Development