Discussion
The structure of B4H10 is given below. Its styx number is
Answer: A
The styx number of B4H10 is 4012.
Lipscomb's code counts four kinds of bond: s = B-H-B bridges, t = three-centre B-B-B bonds, y = two-centre B-B bonds, x = extra terminal H beyond one per boron (BH2 groups). From the structure: 4 bridging hydrogens, no closed B-B-B bond, 1 B-B bond between the two central borons, and 2 BH2 groups (the outer borons), so s, t, y, x = 4, 0, 1, 2.
The balance equations for BpHp+q, here p = 4 and q = 6, confirm it:
\[ \begin{aligned} s + x &= q:\ 4 + 2 = 6 \\ s + t &= p:\ 4 + 0 = 4 \\ t + y &= p - q/2:\ 0 + 1 = 1 \end{aligned} \]
4102 swaps t and y, claiming a three-centre bond the arachno structure does not have. 2104 and 2014 count only two bridges, so they fail the balance \(s + t = p\), giving 2 + 1 = 3 and 2 + 0 = 2 instead of 4.
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