Discussion

What was the day of the week on 28th May, 2006?

Answer: D

Count odd days in stages.

2000 years leave 0. 2001 to 2005 holds one leap year, 2004:

\[ 4(1) + 1(2) = 6 \]

1 January to 28 May 2006, an ordinary year:

\[ 31 + 28 + 31 + 30 + 28 = 148 \equiv 148 - 147 = 1 \pmod 7 \]

\[ \text{total} = 0 + 6 + 1 = 7 \equiv 0 \pmod 7 \]

Zero odd days is Sunday.

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