Discussion
If May 05, 1911 is Friday, then the day on September 11, 1919 is :
Answer: D
September 11, 1919 is a Thursday.
Count the odd days (days beyond whole weeks) from May 5, 1911.
May 5, 1911 to May 5, 1919 is 8 years, including the leap years 1912 and 1916, so 8 + 2 = 10 odd days, which is 3 after removing a week. From May 5 to September 11, 1919: 26 days left in May, then 30, 31, 31 and 11:
\[ \begin{aligned} 26 + 30 + 31 + 31 + 11 &= 129 \\ 129 &= 18 \times 7 + 3 \end{aligned} \]
Total odd days: 3 + 3 = 6. Friday plus 6 days is Thursday. Forgetting the two leap days would give Tuesday, which is not offered.
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