Discussion
A digital oscilloscope with 1 M sample of memory sampling at 100 MSa/s can record for
Answer: A
Correct answer: 10 ms
\[ \frac{10^{6}\ \mathrm{samples}}{100\times10^{6}\ \mathrm{samples/s}} = 10^{-2}\ \mathrm{s} = 10\ \mathrm{ms}. \] Memory depth divided by sample rate is the record length, and the trade it implies governs digital scope use: to capture a longer window the instrument must reduce the sample rate, which reduces the resolution of the fine detail within it.
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