Discussion
Calcining 100 kg of pure CaCO\( _3 \) yields CaO amounting to
Answer: D
Correct answer: 56 kg
The calcination is \( \mathrm{CaCO_3} \rightarrow \mathrm{CaO} + \mathrm{CO_2} \), with molar masses 100, 56 and 44. So 100 kg of pure carbonate yields \[ 100 \times \frac{56}{100} = 56\ \text{kg of lime,} \] the remaining 44 kg leaving as carbon dioxide. That 44 per cent loss is why a cement kiln releases so much carbon dioxide from the raw materials alone, quite apart from the fuel.
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