Discussion
A cement of specific gravity 3.15 occupies, for 50 kg,
Answer: A
Correct answer: about 15.9 litres
Volume is mass divided by density, and a specific gravity of 3.15 means a density of 3150 kg/m³: \[ V = \frac{50}{3150} = 0.0159\ \mathrm{m^3} = 15.9\ \text{litres.} \] This is the figure behind the familiar statement that a 50 kg bag of cement occupies about 0.035 m³ loose - the difference between the two being the voids between the grains.
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