Discussion
A contractor undertakes to do a piece of work in 40 days. He engages 100 men at the begining and 100 more after 35 days and completes the work in stipulated time. If he had not engaged the additional men, how many days behind schedule would it be finished?
Answer: B
Count the man-days actually worked.
\[ 100 \times 35 + 200 \times 5 = 3500 + 1000 = 4500 \]
With only the original 100 men:
\[ \frac{4500}{100} = 45 \text{ days} \]
\[ 45 - 40 = 5 \text{ days behind schedule} \]
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