Discussion
An element 94A238 forms another element B after one α-particle. The atomic number and the atomic mass of the element B will be :
Answer: C
Element B has atomic number and mass 92 and 234 respectively.
An alpha particle is a helium nucleus, two protons and two neutrons, so alpha emission lowers the atomic number by 2 and the mass number by 4:
\[ \begin{aligned} Z &= 94 - 2 = 92 \\ A &= 238 - 4 = 234 \end{aligned} \]
92 and 236 subtracts only 2 from the mass. 95 and 238 is the result of a beta-minus emission, which raises the atomic number by one and leaves the mass unchanged. 93 and 234 takes the right mass loss but the wrong charge loss.
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