Discussion
The number of g-molecule of oxygen in 6.02 x 1024CO molecules is
Answer: C
The answer is 5 gram molecules.
\[n(\mathrm{CO}) = \frac{6.02\times10^{24}}{6.02\times10^{23}} = 10\ \text{mol}\]
Ten moles of CO contain ten moles of oxygen atoms. Since a gram molecule of oxygen is \(\mathrm{O_2}\), \[n(\mathrm{O_2}) = \frac{10}{2} = 5\ \text{mol}\]
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