Discussion
The number of atoms present in 21.6 gram of silver (atomic weight = 108) are same as the molecules in
Answer: B
The answer is 0.2 mole of \(\mathrm{KMnO_4}\).
\[n(\mathrm{Ag})=\frac{21.6}{108}=0.2\ \text{mol}\]
so the sample contains \(0.2\,N_A\) atoms. The option that contains the same number of particles is the one holding 0.2 mole of molecules. For comparison, 1.8 g of \(\mathrm{H_2O}\) and 4.6 g of \(\mathrm{C_2H_5OH}\) are each 0.1 mole.
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