Discussion
The number of waves in n x 10th Bohr's orbit are
Answer: B
The number of waves equals \(n\), the number of the orbit.
De Broglie's standing-wave condition for a stable orbit is \[2\pi r = n\lambda\] so an orbit of principal quantum number \(n\) accommodates exactly \(n\) complete wavelengths, whatever the multiplier in front of it.
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