Discussion
The number of neutrons in dipositive Zinc ion is
Answer: D
The \(\mathrm{Zn^{2+}}\) ion contains 35 neutrons.
Zinc has \(Z=30\) and a mass number of 65, so \[N = A - Z = 65 - 30 = 35\] Forming the dipositive ion removes two electrons; the nucleus is untouched, so the neutron count is unchanged.
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