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An ion \(X^{3+}\) is obtained from an element X (atomic mass 27 and atomic number 13). The number of protons, electrons and neutrons in \(X^{3+}\) is respectively :

  • A.14, 13 and 10
  • B.10, 13 and 14
  • C.13, 13 and 10
  • D.13, 10 and 14

Answer: D

\(X^{3+}\) has 13 protons, 10 electrons and 14 neutrons.

The atomic number, 13, is the number of protons and does not change when an ion forms (the element is aluminium). A neutral atom has 13 electrons; losing three to form a 3+ ion leaves 10. Neutrons = mass number - atomic number = 27 - 13 = 14.

Option 3 (13, 13, 10) forgets that the ion has lost three electrons and puts the electron count in place of the neutrons. Options 1 and 2 change the number of protons, which would make the particle a different element.

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