Discussion
A current source of 15 A with \(2\ \Omega\) resistance in parallel is equivalent to a voltage source of ______ with \(2\ \Omega\) series resistance.
Answer: A
A current source \(I\) with a resistance \(R\) in parallel is converted into a voltage source \(V = IR\) with the same resistance \(R\) in series (source transformation).
\[ V = 15 \times 2 = 30\ \text{V} \]
The series resistance stays at 2 ohms. The values 15 V and 7.5 V come from dividing instead of multiplying, and 5 V has no basis. The answer is 30 V, option A.
No comment is present. Be the first to comment.
Loading…
Post your comment
Please log in or register to post a comment.
Examination Categories
- SSC Exams
- Banking Exams
- Teaching Exams
- Civil Services Exams
- Railways Exams
- Engineering Recruitment Exams
- Defence Exams
- State Government Exams
- Police Exams
- Insurance Exams
- Nursing Exams
- Other Government Exams
- NRA CET
- PG Entrance Exams
- Campus Placement
- MBA Entrance Exams
- CUET and UG Entrance
- Judiciary Exams
- Regulatory Body Exams
- Software Development