Discussion
What is the value of equivalent resistance if a \(40\ \Omega\) resistor is connected in parallel with a \(60\ \Omega\) resistor?
Answer: C
For two resistors in parallel the equivalent resistance is the product over the sum.
\[ \begin{aligned} R_{eq} = \frac{40 \times 60}{40 + 60} \\ &= \frac{2400}{100} = 24\ \Omega \end{aligned} \]
The result is smaller than the smaller resistor, 40 ohms, as it must be for a parallel combination, which rules out 50 ohms and 30 ohms only as being too close to the average. The value 12 ohms is smaller than needed. The answer is 24 ohms, option C.
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