Discussion
If all the people are made to sit in an alphabetical order, in clockwise direction, starting from A, the position of whom amongst the following remains the same (excluding A )?
Answer: B
Correct answer: F
Four face outward and four face the centre, so “left” and “right” must be read from each person’s own seat: facing the centre, the left is clockwise; facing outward, the left is anticlockwise.
E faces outward, so H two seats to E’s right and B three to E’s left are placed at once - and B can only be three seats to H’s right if H too faces outward. D faces the centre with both neighbours facing outward, which rules out every seat but one, and F must then sit beside D. Of the seats left, C and G must be neighbours, which forces A into the seat beside E, with G two to A’s left and C beyond.
Clockwise the circle reads E → A → H → G → C → B → F → D, with E, H and F facing outward and A and D facing the centre.
Keeping A in her seat and running the alphabet clockwise puts B, C, D, E, F, G, H in the seats after her. Comparing with the original circle, only F lands where he already sits - five seats clockwise of A in both arrangements.
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