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Four letter-cluster pairs have been given, out of which three are alike in some manner and one is different. Select the one that is different.

  • A.SX - UZ
  • B.HM - JO
  • C.EJ - GL
  • D.AF - CI

Answer: D

AF - CI is the odd pair. In SX - UZ, HM - JO and EJ - GL each letter of the first cluster moves two places forward in the alphabet to give the second: S to U and X to Z, H to J and M to O, E to G and J to L. In AF - CI the first letter moves two places (A to C) but the second moves three (F to I), so the rule breaks only here. The other three pairs follow one shift of +2 for both letters. Written as steps, S, X to U, Z is +2, +2; H, M to J, O is +2, +2; E, J to G, L is +2, +2; and A, F to C, I is +2, +3, so only the last pair breaks the rule.

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