Discussion
A screen receives \( 1000 \) kg/h containing \( 40 \) per cent undersize. If the underflow is \( 360 \) kg/h and is entirely undersize, the recovery of undersize is
Answer: A
Correct answer: 90 per cent
Find the undersize in the feed, then the fraction of it recovered:
\[ 1000 \times 0.40 = 400\ \mathrm{kg/h\ undersize\ in\ feed} \]
\[ \frac{360}{400} \times 100 = 90\ \mathrm{per\ cent} \]
The remaining 10 per cent of the undersize left with the oversize - the usual consequence of a bed too deep or a residence time too short for every fine particle to reach the deck. The distractor \( 36 \) expresses the underflow as a fraction of the total feed rather than of the undersize in it.
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