Discussion
An indented cylinder rotating at \( 45 \) rev/min has a diameter of \( 0.60 \) m. The peripheral speed is
Answer: C
Correct answer: 1.41 m/s
Peripheral speed is circumference times rotational speed:
\[ v = \pi D N = \pi \times 0.60 \times \frac{45}{60} = 1.885 \times 0.75 = 1.41\ \mathrm{m/s} \]
Speed matters to the separation. Too slow and the short seeds are not carried high enough to clear the bed and reach the trough; too fast and centrifugal force holds every seed in its indent past the trough, so nothing is separated. Each cylinder therefore has a fairly narrow working range of speed.
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