Discussion
A terrain database has a horizontal resolution of 3 arc seconds. At the equator this is approximately
Answer: C
Correct answer: 93 metres
One minute of arc at the equator is one nautical mile, or 1852 metres, so one arc second is about 30.9 metres:
\[ 3 \times 30.9 \approx 93\ \mathrm{metres} \]
This is the resolution of the widely used 3 arc second terrain data. It is adequate for a terrain awareness and warning system, which needs to know the height of the ground ahead, but it is coarse relative to obstacles - a mast or a building falls between posts, which is why obstacle data is held separately as discrete points rather than in the grid.
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