Discussion
The radius of gyration of a circular column of diameter d is :
Answer: B
The radius of gyration is \(\frac{d}{4}\).
Radius of gyration is \(k = \sqrt{I/A}\). For a solid circle \(I = \frac{\pi d^{4}}{64}\) and \(A = \frac{\pi d^{2}}{4}\).
\[ \begin{aligned} k^{2} &= \frac{\pi d^{4}/64}{\pi d^{2}/4} = \frac{d^{2}}{16} \\ k &= \frac{d}{4} \end{aligned} \]
d/2 is the radius, a common slip. The squared options give an area-like quantity, not a length.
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