Discussion
Methane burns completely in air. How many moles of air are needed per mole of methane, taking air as 21 mole per cent oxygen?
Answer: B
Correct answer: 9.52
From \( \mathrm{CH_4 + 2O_2 \rightarrow CO_2 + 2H_2O} \), two moles of oxygen are needed, and air is 21 per cent oxygen: \[ \frac{2}{0.21} = 9.52\ \mathrm{mol\ air}. \] The 4.76 offered is the air per mole of *oxygen*, which is the conversion factor rather than the answer, and 2.00 is the oxygen requirement with the nitrogen forgotten.
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