Discussion
Air enters a combustor at 700 K and leaves at 1500 K, with \( c_p = 1150 \ \mathrm{J/(kg\,K)} \) for the products. The heat added per kilogram is approximately
Answer: A
Correct answer: 920 kJ/kg
\[ q = c_p \Delta T = 1150 \times (1500 - 700) \] \[ = 1150 \times 800 = 920\,000\ \mathrm{J/kg} = 920\ \mathrm{kJ/kg.} \] Note that the temperature difference is what matters, so the same answer follows whether the temperatures are in kelvin or Celsius. Using the exit temperature alone gives 1725 kJ/kg, which is the distractor.
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