Discussion
Nitrogen oxide formation roughly doubles for every 40 K rise in flame temperature. A 120 K rise would increase it by a factor of about
Answer: C
Correct answer: 8
A rise of 120 K is three intervals of 40 K, and each doubles the output, so \[ 2^3 = 8. \] The exponential dependence is why nitrogen oxide emission is so sensitive to peak flame temperature, and why every low-emission combustor design - lean premixed, staged, rich-quench-lean - works by holding that temperature down.
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