Discussion
What will be the output of the following C statement? (assuming the input is “cool brother in city”)
printf("%s\n", argv[argc]);
Answer: A
Correct answer: (null)
argv[argc] is guaranteed to be a null pointer, so the call is printf("%s\n", NULL).
Passing a null pointer to %s is undefined behaviour under the standard, but the GNU C library detects it and prints the literal text (null) rather than dereferencing it - which is the behaviour this key reflects. Other implementations crash instead, so the code should not be written whatever library it happens to meet.
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