Discussion
What is the output of this C code?
#include <stdio.h>
void main()
{
int x = 0;
int *ptr = &5;
printf("%p\n", ptr);
}
Answer: D
Correct answer: Compile time error
& requires an lvalue - something with a storage location - and the literal 5 has none. It is a value, not an object, so the address-of operator has nothing to take the address of.
The compiler rejects the expression outright. Assigning the literal to a variable first, and taking the address of that, is the only way to obtain a pointer to a 5; and a string literal is the special case that does have an address, being an array object in its own right.
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